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Ohm’s law test with answers for grade 8 science (free PDF download)

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Quick answer: Ohm's law says that the current through an ohmic conductor is proportional to the potential difference across it, so V = I × R. This grade 8 science test on ohm's law has 8 questions worth 20 marks, to do in 45 minutes: meters, find the current and unit conversion. The mark scheme is on a separate page; free printable PDF.

Ohm’s law test with answers for grade 8 science (free PDF download)

This grade 8 science test on ohm’s law test works like a real class test. The mark scheme is on a separate page, so revise with the lesson first.

This test lasts 45 minutes and is worth 20 marks. Show the formula, the substitution and the answer with a unit in every calculation. Convert mA and kΩ before you calculate.

Level: Grade 8 science (Year 9 · Class 8) · Curriculum: MS-PS2-3

Ohm’s law test: the test questions

Time: 45 minutes · 8 questions · Total: 20 marks · Calculator allowed

Question 1 Meters (2 marks)

  1. State how an ammeter is connected to a component. (1 mark)
  2. State how a voltmeter is connected. (1 mark)

Question 2 Find the current (3 marks)

A 45 Ω resistor is connected to a 9.0 V battery.

  1. Calculate the current. (2 marks)
  2. The resistance is doubled with the same battery. Calculate the new current. (1 mark)

Question 3 Unit conversion (2 marks)

  1. Convert 330 mA to A. (1 mark)
  2. Convert 2.2 kΩ to Ω. (1 mark)

Question 4 Reading a graph (3 marks)

The graph shows readings for a resistor.

Graph of current against potential difference for a resistor: a straight line through the origin passing 0.10 amperes at 2.5 volts, 0.20 at 5 volts, 0.30 at 7.5 volts and 0.40 at 10 volts024681000.10.20.30.40.5Potential difference V (V)Current I (A)
Current against potential difference for a resistor.
  1. Calculate the resistance. (2 marks)
  2. Use the graph to find the current at 6.0 V. (1 mark)

Question 5 Filament lamp (3 marks)

  1. Explain why the I–V graph of a filament lamp is a curve and not a straight line. (3 marks)

Question 6 An LED resistor (3 marks)

An LED needs 2.0 V and passes 0.020 A. It is in series with a resistor on a 6.0 V supply.

  1. Calculate the potential difference across the resistor. (1 mark)
  2. Calculate the resistance needed. (2 marks)

Question 7 Wet hands (2 marks)

  1. Explain why touching a mains wire with wet hands is more dangerous than with dry hands. (2 marks)

Question 8 Wire resistance (2 marks)

  1. State two ways of lowering the resistance of a metal wire. (2 marks)

See the ohm's law test answers and mark scheme

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