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Mole calculations notes and lesson for GCSE chemistry (free PDF download)

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Mole calculations notes and lesson for GCSE chemistry (free PDF download)

This chemistry grades 9-10 lesson on mole calculations notes gives the key ideas first, then worked examples and diagrams. After that, practise with the worksheet on mole calculations and check yourself with the quiz.

Quick answer: The mole is the chemist’s counting unit: one mole contains 6.02 × 10²³ particles, the Avogadro constant. The mass of one mole, the molar mass M in g/mol, equals the relative formula mass. Use n = m ÷ M to convert between mass and moles, and N = n × 6.02 × 10²³ for particle numbers.

Level: Chemistry grades 9-10 (GCSE · IGCSE · O Level · Class 9-10) · Curriculum: HS-PS1-7, GCSE C3

Mole calculations notes: the key ideas

What is a mole?

Atoms and molecules are far too small to count one by one, so chemists count them in huge, fixed groups called moles. A dozen means 12 of something; a mole means 6.02 × 10²³ of something.

Definition

One mole of a substance contains 6.02 × 10²³ particles (atoms, molecules or ions). The number 6.02 × 10²³ per mole is the Avogadro constant. The symbol for amount of substance is n and the unit is mol.

One mole of carbon atoms has a mass of 12 g, and one mole of water molecules has a mass of 18 g. The mass of one mole is called the molar mass, M, in g/mol. It equals the relative atomic mass or relative formula mass in grams.

Bar chart of the mass of one mole: carbon 12 grams, water 18, sodium chloride 58.5, copper 63.5 and calcium carbonate 100Carbon, C12Water, H₂O18Sodium chloride, NaCl58.5Copper, Cu63.5Calcium carbonate, CaCO₃100mass of 1 mol / g
One mole of each substance contains the same number of particles but has a different mass.

Why use moles at all? A balanced equation compares numbers of particles, but a balance measures mass. Moles let you move from the grams on the balance to the particle ratio in the equation and back again.

How do you find relative formula mass?

Add the relative atomic masses (Ar) of all the atoms in the formula. Multiply by the number outside brackets. Use these values: H 1, C 12, N 14, O 16, Na 23, Mg 24, Al 27, S 32, Cl 35.5, Ca 40, Fe 56, Cu 63.5.

Worked example

Calculate the relative formula mass of calcium hydroxide, Ca(OH)₂.
Mr = 40 + 2 × (16 + 1) = 40 + 34 = 74.
Answer: Mr = 74, so M = 74 g/mol.

How do you convert between mass and moles?

Formula

n = m ÷ M
n = amount of substance in mol, m = mass in g, M = molar mass in g/mol.

Formula triangle with mass m at the top and amount n and molar mass M along the bottommnMcover the quantity you want: n = m ÷ M, m = n × M, M = m ÷ n
The formula triangle for amount, mass and molar mass.
Worked example

How many moles are in 5.85 g of sodium chloride, NaCl?
M = 23 + 35.5 = 58.5 g/mol. n = 5.85 ÷ 58.5 = 0.100.
Answer: 0.100 mol.

Worked example

Calculate the mass of 0.25 mol of calcium carbonate, CaCO₃.
M = 40 + 12 + 3 × 16 = 100 g/mol. m = n × M = 0.25 × 100 = 25.
Answer: 25 g.

How do you count particles?

Multiply the amount in moles by the Avogadro constant to find the number of particles: N = n × 6.02 × 10²³. Divide by the constant to go back from particles to moles.

Conversion map: mass divided by M gives moles, moles multiplied by 6.02 times 10 to the 23 gives particles, and the reverse operations go backmass, mgramsamount, nmolesparticles, Nnumber÷ M× M× 6.02 × 10²³÷ 6.02 × 10²³Moles are the bridge between mass and number of particles.
Moles link mass and number of particles.
QuantitySymbolUnit
Amount of substancenmol
Massmg
Molar massMg/mol
Number of particlesNnone (a count)
Worked example

How many molecules are in 9.0 g of water?
n = 9.0 ÷ 18 = 0.50 mol. N = 0.50 × 6.02 × 10²³ = 3.01 × 10²³.
Answer: 3.0 × 10²³ molecules.

Particle numbers are huge, so write them in standard form and keep the same number of significant figures as the data in the question, usually two or three.

Common mistake

Use the molar mass of the whole particle, not of one atom. Hydrogen gas is H₂, so M = 2 g/mol, not 1 g/mol. Likewise oxygen gas O₂ has M = 32 g/mol.

Lina’s tip

Write the units in your calculation. Grams divided by grams per mole gives moles. If the units do not give the quantity you want, you have turned the formula upside down.

Key points to remember
  • 1 mol = 6.02 × 10²³ particles (Avogadro constant).
  • Molar mass M (g/mol) has the same number as the relative formula mass Mr.
  • n = m ÷ M, so m = n × M (n in mol, m in g, M in g/mol).
  • Number of particles N = n × 6.02 × 10²³.
  • Use the whole particle: M(H₂) = 2 g/mol, M(O₂) = 32 g/mol.

Counting atoms with the mole: frequently asked questions

What is the Avogadro constant?

The Avogadro constant is the number of particles in one mole, 6.02 × 10²³ per mole. It applies to atoms, molecules, ions or any other particles.

How do you calculate the number of moles from mass?

Divide the mass in grams by the molar mass in g/mol: n = m ÷ M. For example, 36 g of water is 36 ÷ 18 = 2.0 mol.

What is the difference between relative formula mass and molar mass?

Relative formula mass has no unit and is found by adding relative atomic masses. Molar mass has the same value but with the unit g/mol, and it is the mass of one mole.

Why do equal moles of different substances have different masses?

A mole always contains the same number of particles, but the particles have different masses. One mole of carbon is 12 g, whereas one mole of copper is 63.5 g.

How do you find the number of atoms in a molecule sample?

First find the number of molecules by multiplying moles by 6.02 × 10²³. Then multiply by the number of atoms in one molecule, for example 3 for water.

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