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Entropy Gibbs energy test with answers for A Level chemistry (free PDF download)

Quick answer: Entropy measures how many ways particles and energy can be arranged; it rises from solid to liquid to gas. This Chemistry 11-12 test on entropy Gibbs energy has 8 questions worth 20 marks, to do in 45 minutes: meaning of entropy, predicting the sign of ΔS and steam reforming: entropy. The mark scheme is on a separate page; free printable PDF.

Entropy Gibbs energy test with answers for A Level chemistry (free PDF download)

This test covers entropy, entropy changes of reactions, the Gibbs equation, a ΔG–T graph and the link to K. You have 45 minutes and may use a calculator. Show your working, convert ΔS to kJ before using it, and use kelvin.

Level: Chemistry grades 11-12 (A Level · IB · Class 11-12) · Curriculum: IB R1.4

Time: 45 minutes · 8 questions · Total: 20 marks · Calculator allowed

Question 2 Predicting the sign of ΔS (3 marks)

State whether ΔS is positive or negative for each change, with a reason.
  1. 2KClO₃(s) → 2KCl(s) + 3O₂(g) (1 mark)
  2. 2NO₂(g) → N₂O₄(g) (1 mark)
  3. Ca²⁺(aq) + CO₃²⁻(aq) → CaCO₃(s) (1 mark)

Question 3 Steam reforming: entropy (3 marks)

In steam reforming, CH₄(g) + H₂O(g) → CO(g) + 3H₂(g). S° values in J K⁻¹ mol⁻¹: CH₄ 186.3, H₂O(g) 188.8, CO 197.7, H₂ 130.7. Calculate ΔS°.

Question 4 Steam reforming: feasibility (2 marks)

For the reaction in the previous question ΔH = +206 kJ/mol. Calculate ΔG at 298 K and state whether the reaction is spontaneous.

Question 5 Steam reforming: temperature (3 marks)

Calculate the minimum temperature at which the reaction becomes spontaneous. Give your answer in kelvin.

Question 6 Reading a ΔG–T graph (3 marks)

The graph shows ΔG against T for a reaction.
  1. State the signs of ΔH and ΔS, with a reason. (1 mark)
  2. Read the temperature at which ΔG = 0. (1 mark)
  3. State the temperatures at which the reaction is spontaneous. (1 mark)
Graph of ΔG against temperature for a reaction: a straight line rising from minus 100 kJ/mol at 0 K to plus 50 kJ/mol at 600 K0100200300400500600−100−50050Temperature T (K)ΔG (kJ/mol)
ΔG against T for a reaction.

Question 7 From ΔG to K (2 marks)

A reaction has ΔG° = −17.0 kJ/mol at 298 K. Calculate the equilibrium constant (R = 8.31 J K⁻¹ mol⁻¹).

Question 8 Entropy of the surroundings (2 marks)

Explain why an exothermic reaction increases the entropy of the surroundings.

See the entropy Gibbs energy test answers and mark scheme

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