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Chemical equilibrium lab answers for A Level chemistry (free PDF download)

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The method and the results are on the chemical equilibrium lab. Do the analysis yourself first, then check the answers below.

Quick answer: Chemical equilibrium is reached when forward and reverse reactions occur at the same rate, so concentrations stay constant. These answers go with the Chemistry 11-12 lab on chemical equilibrium: the graph, the calculations, the uncertainties and the conclusion explained, for all 8 analysis questions.

Chemical equilibrium lab answers for A Level chemistry (free PDF download)

The model answers use the sample absorbances in the results table. Next, check the ICE tables, the units of Kc and the discussion of the standard solution assumption, and compare your own mean Kc with the sample value.

Level: Chemistry grades 11-12 (A Level · IB · Class 11-12) · Curriculum: IB R2.3

Question 2 Initial concentrations

[Fe³⁺]₀ = 0.0200 × V / 10.0: 1.00 × 10⁻², 8.00 × 10⁻³, 6.00 × 10⁻³ and 4.00 × 10⁻³ mol/dm³. [SCN⁻]₀ = 0.00200 × 2.0 / 10.0 = 4.00 × 10⁻⁴ mol/dm³ in every tube.

Question 3 Equilibrium concentrations

Each mole of complex formed uses one mole of Fe³⁺ and one of SCN⁻. tube 1: [Fe³⁺] = 1.00 × 10⁻² − 2.474 × 10⁻⁴ = 9.75 × 10⁻³; [SCN⁻] = 4.00 × 10⁻⁴ − 2.474 × 10⁻⁴ = 1.53 × 10⁻⁴. Also, tube 2: 7.78 × 10⁻³ and 1.76 × 10⁻⁴. Also, tube 3: 5.81 × 10⁻³ and 2.07 × 10⁻⁴. Moreover, tube 4: 3.85 × 10⁻³ and 2.49 × 10⁻⁴ mol/dm³. In addition, these equilibrium values are used in Kc.

Question 4 Calculating Kc

Kc = [Fe(SCN)²⁺] / ([Fe³⁺][SCN⁻]). Also, tube 1: 166 dm³ mol⁻¹; tube 2: 163; tube 3: 160; tube 4: 157.

Question 5 Mean and consistency

Mean = (166 + 163 + 160 + 157) / 4 = 1.6 × 10² dm³ mol⁻¹ (161.5). The values agree within about ±3 %, as expected because Kc is constant at a fixed temperature, even though the concentrations changed. A small downward trend suggests a systematic effect.

Question 6 Assumption in the standard

The true complex concentration in the standard is about 1.87 × 10⁻⁴ mol/dm³, lower than the 2.00 × 10⁻⁴ assumed. Every calculated complex concentration is therefore too high by about 7 %, so the calculated Kc is too high (about 1.6 × 10² against a true value near 1.4 × 10²).

Question 7 Prediction with silver ions

SCN⁻ is removed, so Q becomes greater than K and the equilibrium shifts to the left, making the solution paler. Kc is unchanged because the temperature is the same.

Question 8 Improving the method

Use a calibration series of several standards and a calibration graph of absorbance against concentration, and keep all tubes in a thermostatic water bath at one temperature. Then, repeat each mixture and average.

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