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Transformers notes and lesson for A Level physics (free PDF download)

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Transformers notes and lesson for A Level physics (free PDF download)

This physics grades 11-12 lesson on transformers notes gives the key ideas first, then worked examples and diagrams. After that, practise with the worksheet on transformers and check yourself with the quiz.

Quick answer: An alternating current reverses direction regularly, and its rms value, V₀/√2 for a sine wave, gives the equivalent steady heating effect. A transformer uses electromagnetic induction to change the voltage in the ratio Vs/Vp = Ns/Np. Transmitting power at high voltage reduces the current and so the I²R loss in cables.

Level: Physics grades 11-12 (A Level · IB · Class 11-12) · Curriculum: A Level 3.7.5

Transformers notes: the key ideas

What is alternating current and what are rms values?

In direct current the charges drift one way. In alternating current (ac) they swing back and forth, and the voltage follows a sine wave. Mains electricity in the UK, India, Pakistan, Nigeria and Kenya alternates 50 times per second, while Texas and most of the Americas use 60 Hz.

A voltage that is positive half the time and negative half the time has an average of zero, so we use a more useful measure that tells us the heating effect.

Definition

The root mean square (rms) value of an alternating voltage or current is the value of the direct voltage or current that would deliver the same average power to a resistor. For a sine wave, Vrms = V₀ / √2 and Irms = I₀ / √2, where V₀ and I₀ are the peak values.

A sine wave of voltage against time with the peak value V0 marked by a dashed line and the lower rms value V0 divided by root 2 marked by another dashed linetVV₀VrmsVrms = V₀ / √2 ≈ 0.707 V₀
The rms value is the steady dc voltage that would give the same average power in a resistor. For a sine wave it is 0.707 of the peak.
Formula

P = Vrms Irms = Irms² R = Vrms² / R

P = mean power (W), Vrms = rms voltage (V), Irms = rms current (A), R = resistance (Ω). The frequency is f = 1/T, and ω = 2πf.

Worked example

A kettle is rated 2.3 kW on a 230 V rms supply. Calculate the peak voltage, the rms current and the resistance.

V₀ = √2 × 230 = 325 V. Irms = P/V = 2300 / 230 = 10 A. R = V/I = 230 / 10 = 23 Ω.

How does a transformer work?

A transformer has two coils wound on a shared soft iron core. The alternating primary current produces a changing flux in the core, and by Faraday’s law this induces an alternating emf in the secondary coil. It only works with ac, because a steady flux induces nothing.

A transformer with a laminated iron core, a primary coil on the left connected to an alternating supply and a secondary coil on the right connected to a loadNp turnsNs turns~VploadVslaminated iron coreprimary on the left, secondary on the right
The alternating current in the primary creates a changing flux in the core. This induces an emf in the secondary.
Key law

Vs / Vp = Ns / Np. For an ideal transformer there is no power loss, so VpIp = VsIs. More secondary turns gives a step-up transformer; fewer gives a step-down transformer.

Worked example

A phone charger transformer has 920 primary turns and operates from 230 V. It needs a 12 V secondary. Calculate the secondary turns and, for a 30 W load, the primary current if the transformer is ideal.

Ns = Np Vs/Vp = 920 × 12 / 230 = 48 turns. Ip = P/Vp = 30 / 230 = 0.13 A.

Why is electricity transmitted at high voltage?

The power lost as heat in a cable of resistance R is I²R. For a given power P = VI, raising the voltage lowers the current, so the loss falls with the square of the current. Transformers make this possible, because they change voltage cheaply and efficiently.

Block diagram of electricity transmission from power station through a step-up transformer, high-voltage cables and a step-down transformer to homes, with voltages written under each blockpowerstationstep-uptransformerlongcablesstep-downtransformerhomes25 kV400 kV400 kV11 kV230 Vhigh voltage in the cables means a small current, so I²R loss is small
Power is sent at very high voltage so that the current, and therefore the heat loss in the cables, is small.
Worked example

A farm cooperative sends 20 kW through cables of total resistance 2.0 Ω. Compare the loss at 400 V and at 8000 V.

At 400 V: I = 20 000 / 400 = 50 A, loss = I²R = 50² × 2.0 = 5000 W (25 %). At 8000 V: I = 20 000 / 8000 = 2.5 A, loss = 2.5² × 2.0 = 12.5 W (0.063 %).

What makes a real transformer lose energy?

LossCauseReduced by
Heating of coilsresistance of the wirethick copper wire
Eddy currentscurrents induced in the corelaminated iron core
Hysteresiscore magnetising and demagnetisingsoft iron that magnetises easily
Flux leakagenot all flux links both coilswinding coils on top of each other
Common mistake

Students quote the peak voltage as “the mains voltage”. A mains supply of 230 V is an rms value, so its peak is 325 V.

Lina’s tip

A step-up transformer raises the voltage but lowers the current by the same factor. You never get more power out than you put in, so always check Vp × Ip against Vs × Is.

Key points to remember
  • V_rms = V₀/√2 and I_rms = I₀/√2 for a sine wave.
  • Mean power P = V_rms I_rms = I_rms² R.
  • Ideal transformer: Vs/Vp = Ns/Np and Vp Ip = Vs Is.
  • Power loss in cables: P = I²R, so high voltage means low loss.
  • Transformers need ac, laminated iron cores and thick copper windings.

Rms values, transformers and power lines: frequently asked questions

What does rms stand for and why is it used?

Rms means root mean square. It gives the steady value that would heat a resistor equally, so it lets us compare ac with dc in power calculations.

Why does a transformer not work on direct current?

A direct current gives a constant flux, so Faraday’s law gives no induced emf in the secondary. Only a changing flux induces an emf.

Why does a step-up transformer not give more power?

Energy is conserved. Raising the voltage lowers the current by the same factor, so the output power cannot exceed the input power.

Why are transformer cores laminated?

The thin insulated sheets break up the paths of eddy currents in the iron, which reduces heating and wasted energy.

What is the peak voltage of 230 V mains?

The peak voltage is √2 × 230 V, which is about 325 V. The 230 V figure is the rms value.

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