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Beer-Lambert law notes and lesson for AP Chemistry (free PDF download)

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Beer-Lambert law notes and lesson for AP Chemistry (free PDF download)

This AP Chemistry lesson on Beer-Lambert law notes gives the key ideas first, then worked examples and diagrams. After that, practise with the worksheet on Beer-Lambert law and check yourself with the quiz.

Quick answer: Molarity is moles of solute per litre of solution, and dilution follows M₁V₁ = M₂V₂. Chromatography separates mixtures by how strongly components bind to a stationary phase, measured by R_f. The Beer-Lambert law, A = εbc, shows that absorbance is proportional to concentration, so a calibration line gives the concentration of an unknown.

Level: AP Chemistry · Curriculum: AP Chem Unit 3

Beer-Lambert law notes: the key ideas

How do you measure the concentration of a solution?

Definition

Molarity (M) is the amount of solute in moles per litre of solution: M = n/V. Also, a solution of 0.400 M NaCl contains 0.400 mol of NaCl in every litre of solution, not of solvent.

QuantityDefinitionUnit
Molarity, Mmoles of solute / litres of solutionmol/L
Mass percentmass of solute / mass of solution × 100%
Parts per millionmilligrams of solute per litre of dilute aqueous solutionppm (mg/L)
Mole fraction, xmoles of one component / total molesno unit
Worked example 1

Aarav in Pune dissolves 5.85 g of NaCl (58.44 g/mol) in water and makes up the solution to 250.0 mL. Find the molarity.
n = 5.85 / 58.44 = 0.1001 mol
V = 0.2500 L
M = 0.1001 / 0.2500 = 0.400 mol/L

How do you dilute a solution?

Adding solvent changes the volume but not the amount of solute. Because n = MV is the same before and after, M₁V₁ = M₂V₂. Always add the stock to water, then dilute to the mark of a volumetric flask, since the final volume is what counts, not the volume of water added.

Dilution diagram: 10.0 millilitres of 2.00 molar stock is placed in a 100.0 millilitre volumetric flask and made up to the mark with water to give 0.200 molar solutionstock2.00 M10.0 mL takentransfer+ watermake up to the 100.0 mL markmix0.200 M100.0 mL finaln staysthe sameM₁V₁ = M₂V₂
Dilution keeps the amount of solute constant while the volume grows tenfold.
Worked example 2

How much 2.00 M stock is needed to make 100.0 mL of 0.200 M solution?
V₁ = M₂V₂ / M₁ = (0.200 × 100.0) / 2.00 = 10.0 mL

How does chromatography separate a mixture?

In chromatography a mixture is carried by a mobile phase (the solvent) over a stationary phase (paper or a silica layer). Moreover, each component keeps swapping between the two phases. Also, a component that is attracted more strongly to the stationary phase spends less time in the moving solvent and travels less. On silica, polar molecules stick more strongly, so they move less than nonpolar ones in a nonpolar solvent.

Formula

Rf = distance moved by the spot / distance moved by the solvent front
In addition, both distances are measured from the baseline in the same unit. Rf is a number between 0 and 1 with no unit.

Thin-layer chromatography plate with an ink lane showing two spots at 3.6 cm and 6.0 cm and a reference lane showing a spot at 3.6 cm; the solvent front is 7.5 cm from the baselinebaselineinkref7.5 cm: baseline to solvent frontRf = 3.6 / 7.5 = 0.48Rf = 6.0 / 7.5 = 0.80
A TLC plate: the ink contains the reference dye (same Rf) and a second, less polar dye.

Moreover, the mixture is separated; the spot with Rf = 0.48 matches the reference dye. Other separation methods exploit different properties: filtration separates a solid from a liquid, simple distillation separates a solvent from a dissolved solid, and fractional distillation separates liquids with different boiling points.

What is the Beer-Lambert law?

Also, a coloured solution absorbs some wavelengths of light. In addition, a spectrophotometer sends light of one wavelength through a cuvette and compares the transmitted intensity I with the intensity I₀ through a blank. the transmittance is T = I/I₀ and the absorbance is A = −log T.

Key law

Beer-Lambert law: A = εbc
a = absorbance (no unit), ε = molar absorptivity (L/(mol·cm)), b = path length of the cuvette (cm), c = concentration (mol/L). Also, at fixed wavelength and path length, A is proportional to c.

In addition, choose the wavelength of maximum absorbance, λmax, where the line is steepest and the measurement is most sensitive. Moreover, measure a set of standard solutions, plot absorbance against concentration, and read the unknown from the line.

Calibration graph of absorbance against concentration, a straight line through the origin with five standard points; an unknown sample of absorbance 0.360 corresponds to a concentration of 3.0 times ten to the minus five mole per litre01234560.00.20.40.60.8concentration (10⁻⁵ mol/L)absorbance, Asample: A = 0.360c = 3.0 × 10⁻⁵ mol/LA = εbc
Also, a calibration line: absorbance is proportional to concentration.

Worked examples on the Beer-Lambert law

Worked example 3

In addition, a dye solution in a 1.00 cm cuvette has A = 0.600. For this dye ε = 1.20 × 10⁴ L/(mol·cm). Find c.
c = A/(εb) = 0.600 / (1.20 × 10⁴ × 1.00)
c = 5.00 × 10⁻⁵ mol/L

Transmittance TPercentage TAbsorbance A = −log T
1.00100 %0
0.5050 %0.301
0.2525 %0.602
0.1010 %1.000
Common mistake

Do not subtract the volume of the stock from the final volume when diluting, and do not use a calibration line beyond the highest standard. At high absorbance (above about 1.5) the line bends because too little light reaches the detector, so dilute the sample instead.

Lina’s tip

Also, for any dilution, ask what stays the same: the moles. write n = MV for the stock, set it equal to n = MV for the final solution, and solve for the unknown.

Key points to remember
  • Molarity M = n/V in mol/L; dilution: M₁V₁ = M₂V₂ (moles of solute stay constant).
  • R_f = distance moved by spot / distance moved by solvent front, between 0 and 1.
  • Beer-Lambert law: A = εbc, with ε in L/(mol·cm), b in cm and c in mol/L.
  • a = −log T; T = 50 % gives A = 0.301 and T = 10 % gives A = 1.000.
  • Moreover, use λ_max and a calibration line; dilute samples with A above about 1.5.

Concentration, separation and absorbance: frequently asked questions

What is the difference between molarity and molality?

Molarity is moles of solute per litre of solution and changes slightly with temperature. Molality is moles of solute per kilogram of solvent and does not depend on temperature.

Why does the flask have a mark and not a mass of water to add?

The final volume of the solution is not the same as the sum of the volumes mixed, because solute and solvent occupy space together. A volumetric flask fills the solution to a calibrated mark so the volume is exact.

Why do we measure absorbance at λ_max?

At the wavelength of maximum absorbance, the absorbance changes most for a given change in concentration, so the calibration line is steepest and small differences in concentration are detected more reliably.

What does a blank do in spectrophotometry?

Also, the blank is the solvent and cuvette without the dye. Setting it to A = 0 removes the absorption and reflection of the cuvette and solvent, so the reading depends only on the dye.

Can two different compounds have the same R_f value?

Yes, in one solvent two compounds can have similar R_f values. Matching R_f in several solvents, or using a different technique, gives stronger evidence that two spots are the same compound.

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